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1\section{Ionisation} 
2\label{secioni}
3
4The total cross section at a given incident kinetic energy T is calculated by
5summing the partial cross sections at such energy for all the subshells of an
6element. The partial subshell cross sections at incident energy T are obtained
7from an interpolation of the evaluated cross section data in the EEDL library,
8according to the formula \ref{eqloglog}.
9
10The subshell from which the electron is emitted is randomly selected according
11to the cross sections of the subshells, determined at the energy T by
12interpolating the evaluated cross section data from the EEDL data library.
13
14The probability of emission of an electron ($\delta$ ray) with kinetic energy
15$t$ from a subshell of binding energy $B_i$ as the result of the interaction of
16an incoming electron of kinetic energy $T$ is described by:
17\begin{equation}
18  \label{eqionihigh}
19  Prob(T, t, B_i) = {\sum^7}_{j=2}{a_j(T)\over(t+b_i)^j} 
20\end{equation}
21for $t < t_0$ and
22\begin{equation}
23\label{eqionilow}
24  Prob(T, t, B_i) = {c(T)\over t^2}
25\end{equation}
26for $t > t_0$, where $t_0$ is a parameter.
27Both formulas result from empirical fits to the EEDL data and
28are normalized to 1.
29The $a$, $b$ and $c$ coefficients are
30determined by fitting the data; their energy dependence is evaluated from a
31semilogarithmic interpolation of the fitted data.
32
33The sampling of the final state proceeds
34through two steps: first the range of the energy ($t < t_0$ or $t > t_0$) is
35determined by a random number extraction, taking into account the relative area
36determined by the two functions \ref{eqionihigh} and \ref{eqionilow}, then the
37energy of the $\delta$ ray is generated according to the corresponding
38probability distribution.
39
40The angle of emission of the scattered electron and of the $\delta$ ray
41is determined by energy-momentum conservation.
42
43The interaction leaves the atom in an excited state, with excitation energy
44equal to the binding energy of the subshell from which the electron has been
45emitted. The deexcitation of the atom proceeds via the emission of fluorescence
46photons, as described in section \ref{secphoto}.
47
48\section{Status of the document}
4930.9.99 created by Alessandra Forti
50
51
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