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1\section {Kinky string excitation.}
2
3\hspace{1.0em}Having sampled the configuration of kinky strings 
4we generate outgoing gluon--kink momenta.
5 
6We assume that kinky strings are produced as result of $gg \rightarrow
7gg$ hard interactions. Our generation of the outgoing gluons (kinks)
8momenta is based on the two-jets inclusive production cross section:
9\begin{equation}
10\label{KSE1} \frac{d\sigma_{gg}}{dx_g^{+}dx_g^{-}d\cos{\theta}}=
11 f(x_g^{+},Q^2)f(x_g^{-},Q^2)\frac{d\sigma_{gg}(\hat{s})}{d\cos{\theta}},
12\end{equation}
13where we take $\hat{s}=Q^2=x_g^{+}x_g^{-}s$ and $s$ is the total
14colliding system center of mass energy squared, which calculated using
15 $x_i$ and $q_{ti}$ and $m^2_i$ string end partons. The value
16of $s$ should be large enough to produce gluons with the transverse momentum
17cutoff $Q^2_{0} = 2 \ GeV^2$ choosen.  The QCD gluon -- gluon
18interaction cross section
19\begin{equation}
20\label{KSE2}
21\frac{d\sigma_{gg}(\hat{s})}{d\cos{\theta}} = \frac{9\pi
22\alpha^2_s(Q^2)}{32s}\frac{(3+\cos^2{\theta})^3}{(1-\cos^2{\theta})^2}
23\end{equation}
24was calculated in the Born approximation \cite{CKR77}.  The $\theta$ is
25the scattering angle in the center of mass of the parton-parton system
26and $-z_0 < \cos{\theta} < z_0$ with
27\begin{equation}
28\label{KSE3} z_0 = \sqrt{1 - \frac{4Q^2_0}{sx^{+}x^{-}}}.
29\end{equation} 
30The QCD running coupling constant
31\begin{equation}
32\label{KSE4}\alpha_s(Q^2) = \frac{12 \pi}{25 \ln{(Q^2/\Lambda^2)}},
33\end{equation} 
34which is corresponding to four flavours and $\Lambda^2 = 0.01$ GeV$^2$
35is taken.
36
37$f(x,Q^2)$ is the momentum fraction distribution of gluons in hadron. It
38is choosen from\cite{CKMT95}:
39\begin{equation}
40\label{KSE5}
41f(x,Q^2) = A(Q^2)\frac{x^{-\Delta(Q^2)}}{x}(1 - x)^{n(Q^2)+3} 
42\end{equation}
43with parameters $\Delta(Q^2) = \Delta (1 + \frac{2Q^2}{Q^2 + 1.12})$ and
44$n(Q^2) = \frac{3}{2}(1+\frac{Q^2}{Q^2 + 3.55})$ and $A(Q^2)$ is
45calculated from energy-momentum conservation sum rule.  At $Q^2_{0} = 2
46\ GeV^2$
47\begin{equation}
48\label{KSE6}
49f(x,Q^2_{0}) = 1.71\frac{x^{-0.18}}{x}(1 - x)^{5}.
50\end{equation}
51
52Thus the MC procedure to build the kinky strings can be outlined as
53follows:
54%
55\begin{itemize}
56
57\item Sample $x_i$, ${\bf q_{it}}$ and $m^2_i$, where $i = 1,2,...,2n$,
58 for partons, which will be on the $2n$ string ends for both the soft
59 and kinky strings.
60
61\item For each pair of kinky string calculate total center of mass energy
62$s$ and sample $x^{+}_{min} < x^{+}$ and $x^{-}_{min} < x^{-}$, where
63$x_{min} = 2Q_{0}/\sqrt{s}$
64for ingoing gluon momenta
65using gluon distribution function defined by Eq.($\ref{KSE6}$) at
66$Q^2_0 = 2$ GeV$^2$.
67
68\item Sample the outgoing gluon center of mass scattering angle $\theta$ 
69using Eq. ($\ref{KSE2}$).
70
71\item For each kinky string recalculate parton string end energies and
72momenta.
73
74\end{itemize}
75This procedure should be improved taking into account initial and final state
76gluon radiation.
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