[1208] | 1 | \\ |
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| 2 | $x$ is a kinetic variable of the particle : |
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| 3 | $ x = \log_{10}(\gamma \beta) = \ln(\gamma^{2} \beta^{2})/4.606 $, \linebreak |
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| 4 | and $\delta(x)$ is defined by |
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| 5 | \begin{equation} |
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| 6 | % \label{muion.de1} |
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| 7 | \begin{array}{rll} |
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| 8 | \mbox{for} & x < x_0 : & \delta(x) = 0 \\ |
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| 9 | \mbox{for} & x \in [x_0,\ x_1] : & \delta(x) = 4.606 x - C + a(x_1 - x)^m \\ |
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| 10 | \mbox{for} & x > x_1 : & \delta(x) = 4.606 x - C |
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| 11 | \end{array} |
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| 12 | \end{equation} |
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| 13 | where the matter-dependent constants are calculated as follows: |
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| 14 | \begin{equation} |
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| 15 | % \label{muion.de2} |
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| 16 | \begin{array}{lcl} |
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| 17 | h\nu_p & = & \mbox{ plasma energy of the medium } |
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| 18 | = \sqrt{4\pi n_{el} r_e^3} mc^2/\alpha |
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| 19 | = \sqrt{4\pi n_{el} r_e} \hbar c \\ |
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| 20 | C & = & 1 + 2 \ln (I/h\nu_p) \\ |
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| 21 | x_a & = & C/4.606 \\ |
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| 22 | a & = & 4.606(x_a - x_0)/(x_1 - x_0)^m \\ |
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| 23 | m & = & 3 . |
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| 24 | \end{array} |
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| 25 | \end{equation} |
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| 26 | For condensed media |
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| 27 | $$ |
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| 28 | \begin{array}{ll} |
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| 29 | I < 100 \: \mbox{eV} & \left \{ |
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| 30 | \begin{array}{rll} |
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| 31 | \mbox{for } C \leq 3.681 & x_0 = 0.2 & x_1 = 2 \\ |
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| 32 | \mbox{for } C > 3.681 & x_0 = 0.326 C - 1.0 & x_1 = 2 |
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| 33 | \end{array} \right . \\ |
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| 34 | I \geq 100 \: \mbox{eV} & \left \{ |
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| 35 | \begin{array}{rll} |
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| 36 | \mbox{for } C \leq 5.215 & x_0 = 0.2 & x_1 = 3 \\ |
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| 37 | \mbox{for } C > 5.215 & x_0 = 0.326 C - 1.5 & x_1 = 3 |
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| 38 | \end{array} \right . |
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| 39 | \end{array} |
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| 40 | $$ |
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| 41 | and for gaseous media |
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| 42 | \[ |
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| 43 | \begin{array}{rlll} |
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| 44 | \mbox{for} & C < 10. & x_0 = 1.6 & x_1 = 4 \\ |
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| 45 | \mbox{for} & C \in [10.0,\ 10.5[ & x_0 = 1.7 & x_1 = 4 \\ |
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| 46 | \mbox{for} & C \in [10.5,\ 11.0[ & x_0 = 1.8 & x_1 = 4 \\ |
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| 47 | \mbox{for} & C \in [11.0,\ 11.5[ & x_0 = 1.9 & x_1 = 4 \\ |
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| 48 | \mbox{for} & C \in [11.5,\ 12.25[ & x_0 = 2. & x_1 = 4 \\ |
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| 49 | \mbox{for} & C \in [12.25,\ 13.804[ & x_0 = 2. & x_1 = 5 \\ |
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| 50 | \mbox{for} & C \geq 13.804 & x_0 = 0.326 C -2.5 & x_1 = 5 . |
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| 51 | \end{array} |
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| 52 | \] |
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