source: trunk/source/geometry/solids/specific/src/G4IntersectingCone.cc @ 1350

Last change on this file since 1350 was 1337, checked in by garnier, 14 years ago

tag geant4.9.4 beta 1 + modifs locales

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26//
27// $Id: G4IntersectingCone.cc,v 1.12 2008/04/28 08:59:47 gcosmo Exp $
28// GEANT4 tag $Name: geant4-09-04-beta-01 $
29//
30//
31// --------------------------------------------------------------------
32// GEANT 4 class source file
33//
34//
35// G4IntersectingCone.cc
36//
37// Implementation of a utility class which calculates the intersection
38// of an arbitrary line with a fixed cone
39// --------------------------------------------------------------------
40
41#include "G4IntersectingCone.hh"
42#include "G4GeometryTolerance.hh"
43
44//
45// Constructor
46//
47G4IntersectingCone::G4IntersectingCone( const G4double r[2],
48                                        const G4double z[2] )
49{ 
50
51
52  half_kCarTolerance = 0.5 * G4GeometryTolerance::GetInstance()
53                             ->GetSurfaceTolerance(); 
54  //
55  // What type of cone are we?
56  //
57  type1 = (std::fabs(z[1]-z[0]) > std::fabs(r[1]-r[0]));
58 
59  if (type1)
60  {
61    B = (r[1]-r[0])/(z[1]-z[0]);      // tube like
62    A = 0.5*( r[1]+r[0] - B*(z[1]+z[0]) );
63  }
64  else
65  {
66    B = (z[1]-z[0])/(r[1]-r[0]);      // disk like
67    A = 0.5*( z[1]+z[0] - B*(r[1]+r[0]) );
68  }
69  //
70  // Calculate extent
71  //
72  if (r[0] < r[1])
73  {
74    rLo = r[0]-half_kCarTolerance; rHi = r[1]+half_kCarTolerance;
75  }
76  else
77  {
78    rLo = r[1]-half_kCarTolerance; rHi = r[0]+half_kCarTolerance;
79  }
80 
81  if (z[0] < z[1])
82  {
83    zLo = z[0]-half_kCarTolerance; zHi = z[1]+half_kCarTolerance;
84  }
85  else
86  {
87    zLo = z[1]-half_kCarTolerance; zHi = z[0]+half_kCarTolerance;
88  }
89}
90
91
92//
93// Fake default constructor - sets only member data and allocates memory
94//                            for usage restricted to object persistency.
95//
96G4IntersectingCone::G4IntersectingCone( __void__& )
97{
98}
99
100
101//
102// Destructor
103//
104G4IntersectingCone::~G4IntersectingCone()
105{
106}
107
108
109//
110// HitOn
111//
112// Check r or z extent, as appropriate, to see if the point is possibly
113// on the cone.
114//
115G4bool G4IntersectingCone::HitOn( const G4double r,
116                                  const G4double z )
117{
118  //
119  // Be careful! The inequalities cannot be "<=" and ">=" here without
120  // punching a tiny hole in our shape!
121  //
122  if (type1)
123  {
124    if (z < zLo || z > zHi) return false;
125  }
126  else
127  {
128    if (r < rLo || r > rHi) return false;
129  }
130
131  return true;
132}
133
134
135//
136// LineHitsCone
137//
138// Calculate the intersection of a line with our conical surface, ignoring
139// any phi division
140//
141G4int G4IntersectingCone::LineHitsCone( const G4ThreeVector &p,
142                                        const G4ThreeVector &v,
143                                              G4double *s1, G4double *s2 )
144{
145  if (type1)
146  {
147    return LineHitsCone1( p, v, s1, s2 );
148  }
149  else
150  {
151    return LineHitsCone2( p, v, s1, s2 );
152  }
153}
154
155
156//
157// LineHitsCone1
158//
159// Calculate the intersections of a line with a conical surface. Only
160// suitable if zPlane[0] != zPlane[1].
161//
162// Equation of a line:
163//
164//       x = x0 + s*tx      y = y0 + s*ty      z = z0 + s*tz
165//
166// Equation of a conical surface:
167//
168//       x**2 + y**2 = (A + B*z)**2
169//
170// Solution is quadratic:
171//
172//  a*s**2 + b*s + c = 0
173//
174// where:
175//
176//  a = x0**2 + y0**2 - (A + B*z0)**2
177//
178//  b = 2*( x0*tx + y0*ty - (A*B - B*B*z0)*tz)
179//
180//  c = tx**2 + ty**2 - (B*tz)**2
181//
182// Notice, that if a < 0, this indicates that the two solutions (assuming
183// they exist) are in opposite cones (that is, given z0 = -A/B, one z < z0
184// and the other z > z0). For our shapes, the invalid solution is one
185// which produces A + Bz < 0, or the one where Bz is smallest (most negative).
186// Since Bz = B*s*tz, if B*tz > 0, we want the largest s, otherwise,
187// the smaller.
188//
189// If there are two solutions on one side of the cone, we want to make
190// sure that they are on the "correct" side, that is A + B*z0 + s*B*tz >= 0.
191//
192// If a = 0, we have a linear problem: s = c/b, which again gives one solution.
193// This should be rare.
194//
195// For b*b - 4*a*c = 0, we also have one solution, which is almost always
196// a line just grazing the surface of a the cone, which we want to ignore.
197// However, there are two other, very rare, possibilities:
198// a line intersecting the z axis and either:
199//       1. At the same angle std::atan(B) to just miss one side of the cone, or
200//       2. Intersecting the cone apex (0,0,-A/B)
201// We *don't* want to miss these! How do we identify them? Well, since
202// this case is rare, we can at least swallow a little more CPU than we would
203// normally be comfortable with. Intersection with the z axis means
204// x0*ty - y0*tx = 0. Case (1) means a==0, and we've already dealt with that
205// above. Case (2) means a < 0.
206//
207// Now: x0*tx + y0*ty = 0 in terms of roundoff error. We can write:
208//             Delta = x0*tx + y0*ty
209//             b = 2*( Delta - (A*B + B*B*z0)*tz )
210// For:
211//             b*b - 4*a*c = epsilon
212// where epsilon is small, then:
213//             Delta = epsilon/2/B
214//
215G4int G4IntersectingCone::LineHitsCone1( const G4ThreeVector &p,
216                                         const G4ThreeVector &v,
217                                               G4double *s1, G4double *s2 )
218{
219  G4double x0 = p.x(), y0 = p.y(), z0 = p.z();
220  G4double tx = v.x(), ty = v.y(), tz = v.z();
221
222  G4double a = tx*tx + ty*ty - sqr(B*tz);
223  G4double b = 2*( x0*tx + y0*ty - (A*B + B*B*z0)*tz);
224  G4double c = x0*x0 + y0*y0 - sqr(A + B*z0);
225 
226  G4double radical = b*b - 4*a*c;
227 
228  if (radical < -1E-6*std::fabs(b))  { return 0; }    // No solution
229 
230  if (radical < 1E-6*std::fabs(b))
231  {
232    //
233    // The radical is roughly zero: check for special, very rare, cases
234    //
235    if (std::fabs(a) > 1/kInfinity)
236      {
237      if(B==0.) { return 0; }
238      if ( std::fabs(x0*ty - y0*tx) < std::fabs(1E-6/B) )
239      {
240         *s1 = -0.5*b/a;
241         return 1;
242      }
243      return 0;
244    }
245  }
246  else
247  {
248    radical = std::sqrt(radical);
249  }
250 
251  if (a > 1/kInfinity)
252  {
253    G4double sa, sb, q = -0.5*( b + (b < 0 ? -radical : +radical) );
254    sa = q/a;
255    sb = c/q;
256    if (sa < sb) { *s1 = sa; *s2 = sb; } else { *s1 = sb; *s2 = sa; }
257    if (A + B*(z0+(*s1)*tz) < 0)  { return 0; }
258    return 2;
259  }
260  else if (a < -1/kInfinity)
261  {
262    G4double sa, sb, q = -0.5*( b + (b < 0 ? -radical : +radical) );
263    sa = q/a;
264    sb = c/q;
265    *s1 = (B*tz > 0)^(sa > sb) ? sb : sa;
266    return 1;
267  }
268  else if (std::fabs(b) < 1/kInfinity)
269  {
270    return 0;
271  }
272  else
273  {
274    *s1 = -c/b;
275    if (A + B*(z0+(*s1)*tz) < 0)  { return 0; }
276    return 1;
277  }
278}
279
280 
281//
282// LineHitsCone2
283//
284// See comments under LineHitsCone1. In this routine, case2, we have:
285//
286//   Z = A + B*R
287//
288// The solution is still quadratic:
289//
290//  a = tz**2 - B*B*(tx**2 + ty**2)
291//
292//  b = 2*( (z0-A)*tz - B*B*(x0*tx+y0*ty) )
293//
294//  c = ( (z0-A)**2 - B*B*(x0**2 + y0**2) )
295//
296// The rest is much the same, except some details.
297//
298// a > 0 now means we intersect only once in the correct hemisphere.
299//
300// a > 0 ? We only want solution which produces R > 0.
301// since R = (z0+s*tz-A)/B, for tz/B > 0, this is the largest s
302//          for tz/B < 0, this is the smallest s
303// thus, same as in case 1 ( since sign(tz/B) = sign(tz*B) )
304//
305G4int G4IntersectingCone::LineHitsCone2( const G4ThreeVector &p,
306                                         const G4ThreeVector &v,
307                                               G4double *s1, G4double *s2 )
308{
309  G4double x0 = p.x(), y0 = p.y(), z0 = p.z();
310  G4double tx = v.x(), ty = v.y(), tz = v.z();
311 
312 
313  // Special case which might not be so rare: B = 0 (precisely)
314  //
315  if (B==0)
316  {
317    if (std::fabs(tz) < 1/kInfinity)  { return 0; }
318   
319    *s1 = (A-z0)/tz;
320    return 1;
321  }
322
323  G4double B2 = B*B;
324
325  G4double a = tz*tz - B2*(tx*tx + ty*ty);
326  G4double b = 2*( (z0-A)*tz - B2*(x0*tx + y0*ty) );
327  G4double c = sqr(z0-A) - B2*( x0*x0 + y0*y0 );
328 
329  G4double radical = b*b - 4*a*c;
330 
331  if (radical < -1E-6*std::fabs(b)) { return 0; }   // No solution
332 
333  if (radical < 1E-6*std::fabs(b))
334  {
335    //
336    // The radical is roughly zero: check for special, very rare, cases
337    //
338    if (std::fabs(a) > 1/kInfinity)
339    {
340      if ( std::fabs(x0*ty - y0*tx) < std::fabs(1E-6/B) )
341      {
342        *s1 = -0.5*b/a;
343        return 1;
344      }
345      return 0;
346    }
347  }
348  else
349  {
350    radical = std::sqrt(radical);
351  }
352 
353  if (a < -1/kInfinity)
354  {
355    G4double sa, sb, q = -0.5*( b + (b < 0 ? -radical : +radical) );
356    sa = q/a;
357    sb = c/q;
358    if (sa < sb) { *s1 = sa; *s2 = sb; } else { *s1 = sb; *s2 = sa; }
359    if ((z0 + (*s1)*tz  - A)/B < 0)  { return 0; }
360    return 2;
361  }
362  else if (a > 1/kInfinity)
363  {
364    G4double sa, sb, q = -0.5*( b + (b < 0 ? -radical : +radical) );
365    sa = q/a;
366    sb = c/q;
367    *s1 = (tz*B > 0)^(sa > sb) ? sb : sa;
368    return 1;
369  }
370  else if (std::fabs(b) < 1/kInfinity)
371  {
372    return 0;
373  }
374  else
375  {
376    *s1 = -c/b;
377    if ((z0 + (*s1)*tz  - A)/B < 0)  { return 0; }
378    return 1;
379  }
380}
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