1 | /* Interpolate.c |
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2 | Accelerator Toolbox |
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3 | Created: 14/11/08 |
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4 | Z.Marti zeus@cells.es |
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5 | |
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6 | |
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7 | |
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8 | Numerical recipies functions for 2D interpolation adapted to Matlab |
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9 | * leanguagge |
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10 | |
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11 | */ |
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12 | |
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13 | /*x1a is the direction of the colums: y and x1a the direction of the rows:x*/ |
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14 | |
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15 | |
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16 | /****************************************************************************/ |
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17 | /****************************Bilinear interpolation*****************************/ |
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18 | /****************************************************************************/ |
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19 | |
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20 | void linint(double *x1a, double *x2a, double *ya, int m, int n, double x1, double x2, double *y) |
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21 | { |
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22 | int klo,khi,k,ilo,ihi,i; |
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23 | double u,t,y1,y2,y3,y4,f; |
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24 | |
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25 | if((x1<=x1a[m-1])&&(x1>=x1a[0])&&(x2<=x2a[n-1])&&(x2>=x2a[0])) |
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26 | { |
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27 | ilo=0; |
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28 | ihi=m-1; |
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29 | klo=0; |
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30 | khi=n-1; |
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31 | |
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32 | while (ihi-ilo > 1) |
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33 | { |
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34 | i=(ihi+ilo) >> 1; |
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35 | if (x1a[i] > x1) ihi=i; |
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36 | else ilo=i; |
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37 | } |
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38 | |
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39 | while (khi-klo > 1) |
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40 | { |
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41 | k=(khi+klo) >> 1; |
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42 | if (x2a[k] > x2) khi=k; |
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43 | else klo=k; |
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44 | } |
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45 | y1=ya[ilo+klo*m]; |
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46 | y2=ya[ilo+khi*m]; |
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47 | y3=ya[ihi+khi*m]; |
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48 | y4=ya[ihi+klo*m]; |
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49 | |
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50 | if (x1a[ihi]==x1a[ilo]||x2a[khi]==x2a[klo]) |
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51 | { |
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52 | mexErrMsgTxt("Bad xa input to routine linint"); |
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53 | } |
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54 | |
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55 | else |
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56 | |
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57 | { |
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58 | u=(x1-x1a[ilo])/(x1a[ihi]-x1a[ilo]); |
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59 | t=(x2-x2a[klo])/(x2a[khi]-x2a[klo]); |
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60 | } |
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61 | f=(1-t)*(1-u)*y1+t*(1-u)*y2+t*u*y3+(1-t)*u*y4; |
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62 | |
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63 | } |
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64 | else |
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65 | {/*This is redundant...The limits have been taking as apertures previously*/ |
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66 | /*mexPrintf("Out of Id data range\n");*/ |
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67 | f=sqrt(-1); |
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68 | } |
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69 | *y=f; |
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70 | } |
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71 | |
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72 | |
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73 | /****************************************************************************/ |
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74 | /****************************Cubic interpolation*****************************/ |
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75 | /****************************************************************************/ |
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76 | |
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77 | |
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78 | |
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79 | void splin2(double *x1a, double *x2a, double *ya, double *y2a, int m, int n, double x1, double x2, double *y) |
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80 | { |
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81 | void spline(double *x, double *y, int n, double yp1, double ypn, double *y2); |
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82 | void splint(double xa[], double ya[], double y2a[], int n, double x, double *y); |
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83 | int j,i; |
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84 | double *ytmp,*yytmp,*yaj,*y2aj; |
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85 | |
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86 | ytmp=(double*)mxCalloc(m,sizeof(double)); |
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87 | yytmp=(double*)mxCalloc(m,sizeof(double)); |
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88 | yaj=(double*)mxCalloc(n,sizeof(double)); |
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89 | y2aj=(double*)mxCalloc(n,sizeof(double)); |
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90 | |
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91 | |
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92 | for (j=0;j<m;j++) |
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93 | { |
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94 | /*Take one row of ya and y2a*/ |
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95 | for (i=0;i<n;i++) |
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96 | { |
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97 | yaj[i]=ya[j+i*m]; |
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98 | y2aj[i]=y2a[j+i*m]; |
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99 | } |
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100 | splint(x2a,yaj,y2aj,n,x2,&yytmp[j]); |
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101 | |
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102 | } |
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103 | mxFree(yaj); |
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104 | mxFree(y2aj); |
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105 | |
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106 | spline(x1a,yytmp,m,1.0e30,1.0e30,ytmp); |
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107 | splint(x1a,yytmp,ytmp,m,x1,y); |
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108 | mxFree(ytmp); |
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109 | mxFree(yytmp); |
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110 | |
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111 | } |
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112 | |
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113 | |
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114 | void splie2(double *x1a, double *x2a, double *ya, int m, int n, double *y2a) |
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115 | { |
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116 | void spline(double *x, double *y, int n, double yp1, double ypn, double *y2); |
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117 | int j,i; |
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118 | double *yaj,*y2aj; |
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119 | |
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120 | |
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121 | yaj=(double*)mxCalloc(n,sizeof(double)); |
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122 | y2aj=(double*)mxCalloc(n,sizeof(double)); |
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123 | |
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124 | |
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125 | for (j=0;j<m;j++) |
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126 | { |
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127 | /*Take one row of ya and y2a*/ |
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128 | for (i=0;i<n;i++) |
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129 | { |
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130 | yaj[i]=ya[j+i*m]; |
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131 | y2aj[i]=y2a[j+i*m]; |
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132 | } |
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133 | spline(x2a,yaj,n,1.0e30,1.0e30,y2aj); |
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134 | } |
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135 | mxFree(yaj); |
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136 | mxFree(y2aj); |
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137 | } |
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138 | |
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139 | |
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140 | |
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141 | void spline(double *x, double *y, int n, double yp1, double ypn, double *y2) |
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142 | { |
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143 | int i,k; |
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144 | double p,qn,sig,un,*u; |
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145 | |
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146 | u=(double*)mxCalloc(n-1,sizeof(double)); |
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147 | |
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148 | if (yp1 > 0.99e30) |
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149 | y2[0]=u[0]=0.0; |
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150 | else { |
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151 | y2[0] = -0.5; |
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152 | u[0]=(3.0/(x[1]-x[0]))*((y[1]-y[0])/(x[1]-x[0])-yp1); |
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153 | } |
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154 | |
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155 | |
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156 | for (i=1;i<=n-2;i++) { |
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157 | sig=(x[i]-x[i-1])/(x[i+1]-x[i-1]); |
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158 | p=sig*y2[i-1]+2.0; |
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159 | y2[i]=(sig-1.0)/p; |
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160 | u[i]=(y[i+1]-y[i])/(x[i+1]-x[i]) - (y[i]-y[i-1])/(x[i]-x[i-1]); |
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161 | u[i]=(6.0*u[i]/(x[i+1]-x[i-1])-sig*u[i-1])/p; |
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162 | } |
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163 | |
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164 | if (ypn > 0.99e30) |
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165 | qn=un=0.0; |
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166 | else { |
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167 | qn=0.5; |
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168 | un=(3.0/(x[n-1]-x[n-2]))*(ypn-(y[n-1]-y[n-2])/(x[n-1]-x[n-2])); |
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169 | } |
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170 | |
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171 | |
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172 | y2[n-1]=(un-qn*u[n-2])/(qn*y2[n-2]+1.0); |
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173 | |
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174 | |
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175 | for (k=n-2;k>=0;k--) |
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176 | y2[k]=y2[k]*y2[k+1]+u[k]; |
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177 | mxFree(u); |
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178 | |
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179 | } |
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180 | |
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181 | |
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182 | void splint(double xa[], double ya[], double y2a[], int n, double x, double *y) |
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183 | { |
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184 | int klo,khi,k; |
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185 | double h,b,a; |
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186 | |
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187 | |
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188 | |
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189 | klo=1; |
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190 | khi=n; |
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191 | while (khi-klo > 1) { |
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192 | k=(khi+klo) >> 1; |
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193 | if (xa[k] > x) khi=k; |
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194 | else klo=k; |
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195 | } |
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196 | h=xa[khi]-xa[klo]; |
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197 | if (h == 0.0) mexErrMsgTxt("Bad xa input to routine splint"); |
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198 | a=(xa[khi]-x)/h; |
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199 | b=(x-xa[klo])/h; |
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200 | *y=a*ya[klo]+b*ya[khi]+((a*a*a-a)*y2a[klo]+(b*b*b-b)*y2a[khi])*(h*h)/6.0; |
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201 | } |
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