1 | function [q,r,rflag] = syntheticdivision(snumer,sdenom) |
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2 | % syntheticdivision: quotient and remainder of a synthetic polynomial division |
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3 | % usage: [q,r] = syntheticdivision(snumer,sdenom) |
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4 | % |
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5 | % arguments: (input) |
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6 | % snumer - scalar sympoly object - Numerator polynomial |
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7 | % |
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8 | % sdenom - scalar sympoly object - Denomenator polynomial |
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9 | % |
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10 | % arguments: (output) |
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11 | % q - quotient sympoly |
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12 | % |
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13 | % r - remainder sympoly |
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14 | % |
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15 | % rflag - scalar boolean flag - denotes if the remainder term |
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16 | % was judged to be zero. |
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17 | % |
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18 | % rflag == 0 --> the remainder was zero to within a tolerance |
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19 | % rflag == 1 --> the remainder was greater than the tolerance |
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20 | |
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21 | % are they both sympolys? |
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22 | if ~isa(snumer,'sympoly') |
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23 | snumer = sympoly(snumer); |
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24 | end |
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25 | if ~isa(sdenom,'sympoly') |
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26 | sdenom = sympoly(sdenom); |
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27 | end |
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28 | |
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29 | % monomial sympoly == 0 (right now) |
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30 | monomial = sympoly(1); |
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31 | |
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32 | % make all variable sets the same |
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33 | [snumer,sdenom,monomial] = equalize_vars(snumer,sdenom,monomial); |
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34 | |
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35 | % shift the sympolys to have all positive exponents |
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36 | % The shift will be zero for variables which have all |
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37 | % positive exponents already. |
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38 | sh = min(0,min(snumer.Exponent,[],1)); |
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39 | numershift = monomial; |
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40 | numershift.Exponent = sh; |
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41 | nt = size(snumer.Exponent,1); |
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42 | snumer.Exponent = snumer.Exponent - repmat(sh,nt,1); |
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43 | |
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44 | sh = min(0,min(sdenom.Exponent,[],1)); |
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45 | denomshift = monomial; |
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46 | denomshift.Exponent = sh; |
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47 | nt = size(sdenom.Exponent,1); |
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48 | sdenom.Exponent = sdenom.Exponent - repmat(sh,nt,1); |
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49 | |
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50 | % initialize the quotient and remainder sympolys |
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51 | q = sympoly(0); |
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52 | r = snumer; |
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53 | |
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54 | % highest order term in the denomenator sympoly |
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55 | order = sum(sdenom.Exponent,2); |
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56 | [order,ind] = max(order); |
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57 | denorder = sdenom.Exponent(ind,:); |
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58 | denomcoef = sdenom.Coefficient(ind); |
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59 | |
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60 | % set up a while loop to do the synthetic division |
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61 | divflag = 1; |
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62 | tol = 1e-12*max(abs(snumer.Coefficient))/max(abs(sdenom.Coefficient)); |
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63 | rflag = logical(0); |
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64 | while divflag |
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65 | % find the highest order term in the remainder sympoly |
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66 | order = sum(r.Exponent,2); |
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67 | [order,ind] = max(order); |
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68 | if order>=sum(denorder) |
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69 | % "divide" |
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70 | remorder = r.Exponent(ind,:); |
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71 | remCoef = r.Coefficient(ind); |
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72 | |
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73 | % another piece to add in to q |
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74 | monomial.Exponent = remorder - denorder; |
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75 | monomial.Coefficient = remCoef/denomcoef; |
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76 | q = q + monomial; |
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77 | |
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78 | % and decrement the remainder |
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79 | r = r - monomial*sdenom; |
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80 | r = equalize_vars(r,monomial); |
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81 | |
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82 | % Is there anything left in the remainder that has a |
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83 | % positive exponent? If so, then continue the while loop. |
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84 | if all(r.Exponent(:)<0) |
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85 | divflag = 0; |
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86 | rflag = logical(1); |
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87 | elseif all(r.Exponent(:)<=0) && all(abs(r.Coefficient)<=tol) |
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88 | divflag = 0; |
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89 | end |
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90 | else |
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91 | % there is a non-zero remainder |
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92 | divflag = 0; |
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93 | if any(abs(r.Coefficient)>=tol) |
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94 | rflag = logical(1); |
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95 | end |
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96 | end |
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97 | end |
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98 | |
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99 | % when all is done, unshift the sympolys |
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100 | shift = numershift./denomshift; |
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101 | q = q*shift; |
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102 | r = r*shift; |
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103 | |
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